Questions in mathematics

Questions in mathematics

📝 Answered - The following work models how to write the quotient $\frac{\sqrt[3]{4}}{\sqrt{2}}$ using rational exponents. $\frac{\sqrt[3]{4}}{\sqrt{2}}=\frac{4^{\frac{1}{3}}}{2^{\frac{1}{2}}}=\frac{\left(2^2\right)^{\frac{1}{3}}}{2^{\frac{1}{2}}}=\frac{2^{\frac{2}{3}}}{2^{\frac{1}{2}}}$ Note that, in order to use the quotient property of exponents, the bases must be the same. Using the work shown on the left, what is $\frac{\sqrt[3]{4}}{\sqrt{2}}$ in simplest radical form?

📝 Answered - Jake is planning a trip to China. He has made a list of cities he would like to visit, as well as the approximate amount of money he plans to spend in each as a result of travel, lodging, shopping, and so on. All costs are listed in renminbi (¥). | City | Cost (¥) | | ----------- | -------- | | Tianjin | 557 | | Nanjing | 681 | | Zhengzhou | 595 | | Beijing | 728 | | Wuhan | 449 | | Chengdu | 534 | Unfortunately, Jake only has ¥2,920 available. What is the cheapest city that Jake can remove from his travel plans and still stay under budget? a. Tianjin b. Wuhan c. Nanjing

📝 Answered - Solve the system for [tex]$x$[/tex] and [tex]$y$[/tex]. [tex] \begin{array}{l} 8 x-y=43 \\ 8 x-5 y=-71 \end{array} [/tex]

📝 Answered - 1. $10 \frac{6}{7} - \frac{76}{7} = 10 \frac{6}{7}$ 2. $1 \frac{2}{3} - \frac{8}{6} = 1 \frac{2}{6}$ 3. $12 \frac{4}{6} - \frac{72}{6} = 12 \frac{4}{6}$ 4. $11 \frac{2}{3} - \frac{33}{3} = 11 \frac{2}{3}$

📝 Answered - Werketagraine -es of KI50. (1 mark) $45 \times 202.90=k 12619.20$ Ki2, Gia $20 t+k 150$ Answer: $\qquad$ K12.769.26 Mistrike Answer: $\qquad$ K16740-2 pantis, isteres

📝 Answered - What is the equation of the line that is perpendicular to the given line and passes through the point $(2,6)$? x=2 x=6 y=2 y=6

📝 Answered - Which is equivalent to [tex] \sqrt{10}^{\frac{3}{4} x} [/tex]? A. [tex] (\sqrt[3]{10})^{4 x} [/tex] B. [tex] (\sqrt[4]{10})^{3 x} [/tex] C. [tex] (\sqrt[6]{10})^{4 x} [/tex] D. [tex] (\sqrt[8]{10})^{3 x} [/tex]

📝 Answered - 1) [tex]A=6 a+\{a-2[a+3 b-4(a+b)]\}-13 a[/tex] 2) [tex]B=-[3 x-2 y+(x-2 y)-2(x+y)-3(2 x+1)]-(4 x+6 y)[/tex] [tex]C=n-(x+y)-3(x-y)+2[-(x-2 y)-2(-x-y)]+2 x-10 y[/tex]

📝 Answered - Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar. $\overleftrightarrow{A B}$ and $\overleftrightarrow{B C}$ form a right angle at their point of intersection, $B$. If the coordinates of $A$ and $B$ are $(14,-1)$ and $(2,1)$, respectively, the $y$-intercept of $\overleftrightarrow{A B}$ is $\square$ and the equation of $B C$ is $y=\square x+\square$. If the $y$-coordinate of point $C$ is 13 , its $x$-coordinate is $\square$

📝 Answered - Determine the value of [tex]$x$[/tex] for which the function [tex]$f(x)=\left\{\begin{array}{l}5 x, \text { if } x<0 \\ 1, \text { if } x=0 \\ -5 x, \text { if } x>0\end{array}\right.$[/tex] is discontinuous. a) 1 b) 0 c) 5 d) -5