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Questions in mathematics

📝 Answered - How many solutions will each system of linear equations have? Match the systems with the correct number of solutions. infinitely many solutions no solution one solution [tex]y=-4 x+11[/tex] and [tex]-6 x+y=11[/tex] [tex]y=-2 x+5[/tex] and [tex]2 x+y=-7[/tex] [tex]y=x+6[/tex] and [tex]3 x-3 y=-18[/tex]

📝 Answered - Consider the following equation: [tex]4 x+y=1[/tex] Determine if the given ordered pair [tex](1,-3)[/tex] satisfies the given equation.

📝 Answered - Factor the quadratic $6 x^2-5 x-6$. List ONLY ONE of the factors with parentheses and no spaces. Example: $(x+1)$

📝 Answered - Which of the points listed below are solutions for the system? [tex]\begin{array}{l} 7 y\ \textgreater \ 7 x \\ 3(x-2)\ \textless \ 0 \\ \text { I. }(-1,3) \\ \text { II. }(-5,9) \\ \text { III. }(0,0) \end{array}[/tex] a. I, II and III b. I and II c. I only d. I and III

📝 Answered - What is the solution set of the equation [tex]$x^2+3 x-4=6 ?$[/tex] A. [tex]$\{-5,2\}$[/tex] B. [tex]$\{-2,-1\}$[/tex] C. [tex]$\{2,7\}$[/tex] D. [tex]$(5,10)$[/tex]

📝 Answered - Elliott has eight numbered cards. One of the cards is chosen at random. Elliott says: * The probability of an 8 is [tex]$\frac{1}{4}$[/tex] * The range of the numbers is 5. * The probability of a number greater than 10 is 0. * The probability of a 7 is [tex]$\frac{1}{2}$[/tex] Fill in the six missing numbers.

📝 Answered - Introduction to Scatter Plots: Tutorial Christina researched 10 sedans and recorded their prices and the number of stars they were given. The table contains her data. Which points on the graph represent this data? Stars Price (thousand dollars) 3 14 3.5 16 5 21 4.5 18 3 16 4 22 4.5 24 2 13 2 15

📝 Answered - Simplify the following expression: [tex]$\begin{array}{l}\left(4 m^3+6\right)-\left(-2 m^3+m^2+3\right) \\ 6 m^3+5 m^2-3 \\ 6 m^3-m^2+3 \\ 6 m^3+m^2+3 \\ 2 m^3+m^2+9\end{array}$[/tex]

📝 Answered - Solve the equation by using the quadratic formula. [tex]2 x^2-5 x=7[/tex] A. [tex]x=\frac{2}{7},-1[/tex] B. [tex]x=\frac{2}{7}, 0[/tex] C. [tex]x=\frac{7}{2},-1[/tex] D. [tex]x=\frac{2}{7}, 1[/tex]

📝 Answered - Rewrite without rational exponents, and simplify, if possible. $\left(a^2 b^2\right)^{\frac{1}{9}}$