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Questions in chemistry

📝 Answered - What is the conjugate acid in the following reaction: [tex]$HCl ( aq )+$[/tex] [tex]$H _2 O ( i ) \rightarrow Cl ^{-}( aq )+ H _3 O ^{+}( aq ) ?$[/tex] A. [tex]$H _2 O$[/tex] B. [tex]$Cl ^{-}$[/tex] C. [tex]$H _3 O ^{+}$[/tex]

📝 Answered - Consider this reaction: $KOH + HBr \rightarrow KBr + H _2 O$ Which is the base in this reaction? A. KOH B. HBr C. KBr D. $H _2 O$

📝 Answered - Calcium carbonate reacts with HCl to give CaCl₂ and CO₂ according to the reaction: CaCO₃(s) + 2HCl(aq) → CaCl₂(aq) + CO₂(g) + H₂O(l) What mass of 20% impure CaCO₃ is required to react completely with 250 ml of 0.50 M HCl? (1) 6.25 g (2) 5 g (3) 4.75 g (4) 7.8 g

📝 Answered - A student prepares 150.0 mL of 1.40 M HCl using 35.0 mL of a stock solution. What is the concentration of the stock solution?

📝 Answered - What else is produced during the replacement reaction of silver nitrate? [tex]2 AgNO_3+K_2 SO_4 \rightarrow Ag_2 SO_4+ KNO _3[/tex] A. [tex]2 KNO _3[/tex] B. [tex]K _2[/tex] C. [tex]2 AgNO _3[/tex]

📝 Answered - How can the effect of heat on a reaction be determined? A. Heat always shifts a reaction toward reactant formation. B. Heat is treated as a reactant or a product. C. Heat will increase reaction rate, but not equilibrium position. D. Heat always shifts a reaction toward product formation.

📝 Answered - What is the hydronium ion $[H_3 O^+]$ concentration for a $6.42 \times 10^{-9} M [OH^-]$ solution?

📝 Answered - Materials | | Visible | Not Visible | Uniform | NonUniform | State of Matter | |-----------|---------|-------------|---------|------------|-----------------| | 1. Sugar and water | | | | | | | 2. Oil and water | | | | | | | 3. Vinegar and water | | | | | | | 4. Salt and pepper | | | | | | | 5. leaf and water | | | | | |

📝 Answered - Consider the reaction below. [tex]PCl_5(g) \longleftrightarrow PCl_3(g)+Cl_2(g)[/tex] At 500 K, the reaction is at equilibrium with the following concentrations. [tex] \begin{array}{l} \left.PCl_5\right]=0.0095 M \\ \left.PCl_3\right]=0.020 \\ \left.Cl_2\right]=0.020 M \end{array} [/tex] What is the equilibrium constant for the given reaction?

📝 Answered - Label A-F based on the table using C for concentrated and D for dilute. A $\square$ F B $\square$ C $\square$ D $\square$ E $\square$ F $\square$ | acid/base | molarity | concentrated/dilute | |---|---|---| | HCI | 12 M | A | | | 0.5 M | B | | NaOH | 0.01 M | C | | | 6.0 M | D | | $H _2 SO _4$ | 0.05 M | E | | | 10 M | F |