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Questions in Grade High-school

📝 Answered - Suppose a survey of adults and teens (ages 12-17) in a certain country was conducted to determine the number of texts sent in a single day. (a) Construct a relative frequency distribution for adults. (b) Construct a relative frequency distribution for teens. (c) Construct a side-by-side relative frequency bar graph. (d) Compare the texting habits of adults and teens. \begin{tabular}{lcc} \hline Number of Texts & Adults & Teens \\ \hline None & 164 & 16 \\ \hline $1-10$ & 974 & 147 \\ \hline $11-20$ & 257 & 70 \\ \hline $21-50$ & 254 & 122 \\ \hline $51-100$ & 135 & 115 \\ \hline $100+$ & 147 & 189 \\ \hline \end{tabular} (a) Complete the table below. \begin{tabular}{l|l|l} \hline Number of Texts & \multicolumn{2}{c}{ Adults } \\ \hline None & & \\ \hline $1-10$ & & \\ \hline $11-20$ & & \\ \hline $21-50$ & & \\ \hline $51-100$ & & \\ \hline $100+$ & & \\ \hline \end{tabular} (Round to three decimal places as needed.)

📝 Answered - $6 \sqrt{11}+\sqrt[3]{4.4}-1.83^5$

📝 Answered - What are the values of $a_1$ and $r$ of the geometric series? $2-2+2-2+2$ A. $a_1=2$ and $r=-2$ B. $a_1=-2$ and $r=2$ C. $a_1=-1$ and $r=2$ D. $a_1=2$ and $r=-1$

📝 Answered - Subtract. [tex]$\frac{b+7}{3 b}-\frac{9 b+7}{4 b}$[/tex]

📝 Answered - Simplify [tex]\frac{5^5 \cdot 6^3 \cdot 8^{10}}{5^3 \cdot 6 \cdot 8^9}[/tex].

📝 Answered - Simplify each expression. 1. [tex]3^8 \cdot 3=[/tex]

📝 Answered - Solve the equation. $5 x+4=-8+2 x+18$

📝 Answered - There are 6 tiles numbered 1 to 6 in a box. Two tiles are selected at random without replacement to form a 2-digit number where the first number picked is the tens digit and the second number picked is the ones digit. Jeffrey found the probability that the number selected is 16 as shown. Explain his error. The number of ways to select 1 and 6 is given by ${ }_6 c_2=15$ $P(16)=\frac{1}{{ }_6 C_2}=\frac{1}{15}$

📝 Answered - Write 0.46 as a fraction.

📝 Answered - 1.7 meters to millimeters