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Questions in Grade High-school

📝 Answered - \frac{x-6}{x^2+5 x-24}

📝 Answered - (-1,4) and (1,-1) find the distance

📝 Answered - What is the following quotient? $\frac{1}{1+\sqrt{3}}$

📝 Answered - Write an equivalent expression by distributing the "-" sign outside the parentheses: $(2.9 c+1)$

📝 Answered - Sandy is trying to reconstruct her spending pattern from July. She knows that she had $277 in her account on July 1, but after that, her receipts and balance statements are all scrambled. Here are Sandy's records: | Date | Transaction Type | Amount ($) | | :----- | :--------------- | :--------- | | 7/26 | Purchase | 86 | | 7/25 | Deposit | 76 | | 7/4 | Purchase | 137 | | 7/6 | Deposit | 90 | | 7/10 | Purchase | 131 | | 7/9 | Purchase | 145 | | 7/15 | Deposit | 152 | | 7/19 | Purchase | 137 | Assuming that this is a complete, if scrambled, record of Sandy's July spending and that any overdraft fees incurred do not affect the running total, how many times did Sandy overdraw her account in July? A. Sandy never overdrew her account. B. Sandy only overdrew her account once. C. Sandy overdrew her account twice.

📝 Answered - Each data pair shown is of the form below: (years since purchase, value of car) Based on the correlation coefficient, there is a(n) __________ linear correlation between the data. Linear Regression [tex]y=-3223.31 x+31805.583 ; r=-0.988[/tex] [tex]-0.7000\ \textless \ x \leq 7.7[/tex] [tex]\text { Window: } 8913.1 \leq y \leq 33007.9[/tex]

📝 Answered - $\frac{9-|3-7|}{2^{-1}}$

📝 Answered - $(7 x^2-3 x+23)-(9 x^2-x-8)

📝 Answered - Solve for x. $-3(2 x-1)-4 x+3=26$

📝 Answered - Let's try a problem. You heat 2.0 kg of water to make pasta. The temperature of the water before you heat it is [tex]$40^{\circ} C$[/tex]. The temperature of the water after you heat it is [tex]$100^{\circ} C$[/tex]. How much heat was transferred to the water? (The specific heat of water is [tex]$4,184 J / kg \cdot{ }^{\circ} C$[/tex]). Step 1: Write the equation. heat = specific heat [tex]$\times$[/tex] mass [tex]$\times$[/tex] change in temperature Step 2: Place values into the equation, and solve. [tex]$\text { heat }=4,184 J / kg \cdot{ }^{\circ} C \times 2.0 kg \times\left(100^{\circ} C-40^{\circ} C\right)=502,080 J . $[/tex] The heat transferred is [tex]$502,080 J$[/tex]. Calculate Use the data in the figure to determine the energy needed to warm the water in the cup.