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Questions in Grade High-school

📝 Answered - -2(4x - 13) = -13x - 14

📝 Answered - $\frac{4<2 x<6}{222}$ 21. Most snakes live where the temperature ranges from $73^{\circ} F$ to $92^{\circ} F$. Write an inequality for the temperature where snakes will NOT thrive.

📝 Answered - 1. $\left\{-9,-\frac{7}{2}, 5, \frac{2}{3}, \sqrt{3}, 0,8,-4,2,-11\right\}$ a. Natural Numbers: b. Whole Numbers: c. Integers: $\{-11,-9,-4,0,2,5,8\}$ d. Rational Numbers: e. Irrational Numbers:

📝 Answered - Which of the following statements show a TRUE cause and effect statement? CHOOSE THREE A. Because they were competing for land and power, tensions between European countries rose. B. Because Spanish settlers set up missions along the coastline, many Natives were forced to convert to Christianity. C. Because they had better weapons, Hernando de Soto and his men were not able to find gold. D. Because they had never encountered European diseases, over half of the Native Americans died due to impaired immune systems.

📝 Answered - If [tex]$TU = x+7$[/tex], [tex]$UV = 5x$[/tex], and [tex]$TV = 8x-5$[/tex], what is [tex]$UV$[/tex]?

📝 Answered - Given [tex]$\cos \theta=\frac{4 \sqrt{2}}{7}$[/tex], what is [tex]$\sin \theta$[/tex]? [tex]$\sin \theta=\underline{\sqrt{[?]}}$[/tex] Report your answer in simplest form.

📝 Answered - Solve: [tex]$\frac{4}{x}=\frac{5}{x}-\frac{1}{2}$[/tex]

📝 Answered - What are the zeros of the polynomial function? Select all correct zeros of each function. \begin{tabular}{l|ll} \hline Function & -3 & -2 \\ \hline$f(x)=2 x(x-3)(2-x)$ & & -1 \\ \hline$f(x)=2(x-3)^2(x+3)(x+1)$ & & 0 \\ \hline$f(x)=x^3(x+2)(x-1)$ & & \end{tabular}

📝 Answered - 3) $5.97 \times 10^9 L+0 GL$

📝 Answered - Determining If the Inverse Is a Function The formula [tex]F(C)=\frac{9}{5} C+32[/tex] calculates the temperature in degrees Fahrenheit, given a temperature in degrees Celsius. You can find an equation for the temperature in degrees Celsius for a given temperature in degrees Fahrenheit by finding the function's inverse. Check all that apply. A. [tex]F[/tex] is a function. B. [tex]F[/tex] is a one-to-one function. C. [tex]C[/tex] is a function. D. [tex]C[/tex] is a one-to-one function. The inverse of [tex]F(C)=\frac{9}{5} C+32[/tex] is [tex]C(F)=5 / 9 F-160 / 9[/tex]