If a woman is homozygous for type A blood and her husband is type O, what is the probability that their offspring would have any one of the 4 possible blood types.
Answer (3)
Answer:
The offspring would have type A blood group.
The genotype of mother would be I A I A (homozygous type A blood group).
Thus, she will produce only one type of gamete that is, I A .
Similarly, the genotype of a the father would be *ii *(type O blood group).
He will also produce only one type of gamete that is, i.
The cross would produce offspring with genotype I A i .
Thus, the offspring would have only type A blood group.
Hence, the probability of having blood group A would be 100% and probability of having other blood group (B, AB or O) would be zero %.
The four blood types are A, B, AB and OThe probability that their offspring would have A blood type is 100%. Since one of the parents is homozygous for type A blood while the other is type O
The probability that their offspring would have B blood type is zero (0) since neither of the parents have B antigene
The probability that their offspring would have AB blood type is zero (0) since neither of the parents have B antigene.
The probability that their offspring would have B blood type is zero (0) since only one of the parents have O antigene. The other parent is homozygous for type A, which means the antigens are AA.
The offspring of a homozygous type A mother and a type O father will only have type A blood. Therefore, the probability of having type A is 100%, and the probability of having blood types B, AB, or O is 0%.
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