Solving systems by elimination:

\[ 2x + 4y = -4 \]
\[ 3x + 5y = -3 \]

Please show your work.

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Answered by juventusmarc | 2024-06-12

2 x + 4 y = − 4 ( / ∗ 3 ) 3 x + 5 y = − 3 ( / ∗ ( − 2 )) ⇒
6 x + 12 y = − 12 − 6 x − 10 y = 6 ⇒
2 y = − 6 ⇒ y = − 3 y = − 3 ⇒ 2 x + 4 y = − 6 → 2 x + 4. ( − 3 ) = − 6 ⇒ 2 x − 12 = − 6 ⇒ 2 x = 6 ⇒ x = 3
( x , y ) = ( 3 , − 3 )

Answered by turk3005 | 2024-06-24

To solve the system 2 x + 4 y = − 4 and 3 x + 5 y = − 3 using elimination, we scaled the equations to eliminate x and found y = − 3 . Substituting back gives us x = 4 . The final solution is ( x , y ) = ( 4 , − 3 ) .
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Answered by turk3005 | 2024-09-03