Solve the equation. [tex]$16+19=-5(6 x-7)$[/tex]

OK so 3r^2-16r-7=5
Subtract five from both sides
3r^2-16r-7-5=0
Add like terms
3r^2-16r-12=0
Factorise it, this means putting it into brackets
(3r + 2)(r - 6)
Find out what multiplies to make negative twelve but adds to make negative sixteen
However none of the terms do this so we put negatives next to the "r"s
(-3r + 2)(-1r - 6)
The answer is r=6

Answered by Anonymous | 2024-06-10

Step 1: Subtract 5 from both sides.
3r2−16r−7−5=5−5
3r2−16r−12=0
Step 2: Factor left side of equation.
(3r+2)(r−6)=0
Step 3: Set factors equal to 0.
3r+2=0 or r−6=0
r=−2/3
or r=6
Answer:
r=−2/3
or r=6 ;

Answered by nuneesoofinee | 2024-06-12

To solve the equation 3 r 2 − 16 r − 7 = 5 , we first rearrange it to 3 r 2 − 16 r − 12 = 0 . Then, we factor it into ( r − 6 ) ( 3 r + 2 ) = 0 , giving solutions r = 6 and r = − 3 2 ​ . The primary solution to consider is r = 6 .
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Answered by Anonymous | 2024-12-17