The monthly mean salaries and standard deviations of four college students are given below.
\begin{tabular}{|c|c|c|}
\hline Student & Mean & Standard Deviation \\
\hline Clarissa & $345 & 12.53 \\
\hline Abi & $598 & 8.99 \\
\hline Kaila & $812 & 15.29 \\
\hline Shenika & $208 & 7.67 \\
\hline
\end{tabular}
Which statement must be true?
A. The monthly salary of Shenika is less spread out than the monthly salary of Clarissa.
B. The monthly salary of Kaila is less spread out than the monthly salary of Abi.
C. The monthly salary of Abi is less spread out than the monthly salary of Shenika.
D. The monthly salary of Clarissa is less spread out than the monthly salary of Abi.
Answer (2)
We will call the first number n, and the second number x.
3n-x=118
2n+x=147
Now, solve one of the equations for x.
x=147-2n
Then, substitute this into the other formula for x.
3n-(147-2n)=118
Next, solve for n:
3n-147+2n=118 5n=265 n=53 ^^^That's your first number.
Lastly, plug in 53 for n into either equation to solve for x.
2(53)+x=147 106+x=147 x=41 ^^^This is your second number.
The two numbers Juan is thinking of are 53 and 41. The first number is 53, and the second number is 41. These values satisfy both equations given in the problem.
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