Find and classify the critical points of [tex]$z=\left(x^2-2 x\right)\left(y^2-7 y\right)$[/tex]

Local maximums: $\square$
Local minimums: $\square$
Saddle points: $\square$

Jacob's mistake is in the** improper labeling** of his points as x(0,2) and y(4,3). The correct notation should be (0,2) and (4,3). Once corrected, the slope of the line passing through these points is found to be 0.25. ;

Answered by ViolaDavis | 2024-06-18

The named points should be **stated **as (0,2) and (4,3), not x(0,2) and y(4,3). The slope of the line is calculated using the formula m=(y2-y1)/(x2-x1). These give a slope, m, of 0.25. ;

Answered by RachelMeghanMarkle | 2024-06-18

Jacob's mistake was in the way he labeled his points; they should be referred to simply as (0,2) and (4,3). The slope of the line through these points is calculated using the formula for slope, resulting in a value of 0.25. Therefore, his final notation and calculation needed correction.
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Answered by ViolaDavis | 2024-10-16