Until a train is a safe distance from the station, it must travel at [tex]$5 m / s$[/tex]. Once the train is on open track, it can speed up to [tex]$45 m / s$[/tex]. If it takes a train 8 seconds to reach [tex]$45 m / s$[/tex], what is the acceleration of the train? (Round your answer to the nearest whole number.)
Answer (2)
Well, the configuration is 1 s 2 2 s 2 2 p 5 . To show the electrons, we have 1s as [ ], 2s as [ ], 2p as [ ][ ][*-], where * is an electron and - is a vacant slot. We have 5 occupied orbitals (4 fully occupied, one partially occupied)
A fluorine atom in its ground state has a total of 5 occupied orbitals. This includes 1 orbital from the 1s subshell, 1 from the 2s subshell, and 3 from the 2p subshell. The electron configuration can be noted as 1sĀ² 2sĀ² 2pāµ.
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