Find the sum of the first 47 terms of the arithmetic sequence. [tex]
\begin{array}{l}
30,41,52,63 \\
a_1=30 \\
d=11
\end{array}
[/tex]

g = number of girls; b= number of boys we know that: g= 6+2b and that: g+b= 156 kids in total so we may write g+b=(6+2b)+b=6+3b but g+b= 156 so 6+3b = 156 => 3b= 156-6=150 => b=150/3=50 => b = 50 (number of boys) g= 6+2b= 6+2 x 50= 106 => g =106 (number of girls)

Answered by daniela88 | 2024-06-24

To find the number of boys and girls at the camp, use the 5-d process. With the given information, we can set up equations and solve for the values of B and G. ;

Answered by DemetriaGene | 2024-06-24

In total, there are 50 boys and 106 girls at the Cyber summer camp. This was calculated by setting up equations based on the given relationships between the number of boys and girls. Using substitution, we found the values of both variables based on the total number of students.
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Answered by daniela88 | 2024-10-01