Use the IVT to determine if there is a solution to [tex]f(x)=-9[/tex] in the interval between -2 and 4. If so, find the value of [tex]c[/tex] in the interval such that [tex]f(c)=-9[/tex].
* [tex]f(x)[/tex] is continuous on [-2,4]
* -9 is not between -2 and 4 so the IVT does not apply
* [tex]f(x)[/tex] is continuous on [-2,4]
* -9 is between [tex]f(-2)=24[/tex] and [tex]f(4)=-24[/tex]
* [tex]c=1[/tex]
* [tex]f(x)[/tex] is continuous on [-2,4]
* -9 is between [tex]f(-2)=24[/tex] and [tex]f(4)=-24[/tex]
* [tex]c=9[/tex]
* [tex]f(x)[/tex] is continuous on [-2,4]
* -9 is between [tex]f(-2)=24[/tex] and [tex]f(4)=-24[/tex]
* [tex]c=1, c=9[/tex]
Answer (2)
A=24xD 3/5xD=1/2xA 3d/5=12 d=12x5/3 d=20 a=480
Devi has 120 cards, and since Anne has 24 more cards than Devi, Anne has 144 cards. The relationship between their cards was established using fractions, which helped solve for Devi's cards first. Once Devi's total was known, it was easy to calculate Anne's total cards.
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