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In Mathematics / College | 2025-08-20

Problems 15-16: Use the table below to determine the degree of the polynomial.

15.

\begin{tabular}{|c|c|c|c|c|c|c|c|}
\hline$x$ & -3 & -2 & -1 & 0 & 1 & 2 & 3 \\
\hline$g(x)$ & 30 & 15 & 4 & -3 & -6 & -5 & 0 \\
\hline
\end{tabular}

Asked by armannsingh77

Answer (3)

I'm not sure if the answer is right, but here you go.
y=mx+b
'm' is for gradient of the line. First, calculate the gradient.
Let's use (6,15) and (8,21)
Gradient, m = y 2 ​ - y 1 ​ -------------- x 2 ​ - x 1 ​ = 21 - 15 = 6 = 3 ----------- ---- 8 - 6 2 Therefore, m = 3 . Now let's search 'b' . Let's use (6,15) again. Substitute it into the equation.
y=mx+b 15 = 3 (6) + b b = -3
Thus, the equation : y=3x -3

Answered by Anonymous | 2024-06-10

Answer: Use Desmos.com/calculator ;

Answered by isaacf1890 | 2024-06-24

The equation for the relation represented by the points (6, 15), (8, 21), and (10, 27) is y = 3 x − 3 . This was derived by calculating the slope and y-intercept using the formula y = m x + b . By substituting the points into the equation, we confirmed its accuracy.
;

Answered by Anonymous | 2024-12-24

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