0. [tex]$h(x)$[/tex] is an even function. Find the values of [tex]$a, b, c$[/tex], and [tex]$d$[/tex].


| [tex]$x$[/tex] | -4 | [tex]$b$[/tex] | -2 | -1 | 1 | 2 | 3 | 4 |
|---|---|---|---|---|---|---|---|---|
| [tex]$h(x)$[/tex] | [tex]$a$[/tex] | 6 | 5 | 1 | 1 | [tex]$c$[/tex] | [tex]$d$[/tex] | 91 |

The answer is 88 because if u divide by seven the highest it can reach it 84 which has a remainder of 4 while if we divide it with 88 the remainder is 8 so its 88

Answered by deathstrike001 | 2024-06-10

Add 3 to get a multiple of 7 with last digit 1. The only number in that range is 91, so our number is 88.

Answered by Anonymous | 2024-06-10

The number that is more than 50 but less than 100, with a remainder of 4 when divided by 7 and a remainder of 8 when divided by 10, is 88. This satisfies all given conditions. Verification shows that dividing 88 by both 7 and 10 gives the correct remainders.
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Answered by deathstrike001 | 2024-09-26