Given [tex]$\sin heta=\frac{\sqrt{5}}{3}$[/tex], what is [tex]$\cos heta$[/tex]? Report your answer in simplest form. [tex]$\cos heta=[?]$[/tex]

Question

Given [tex]$\sin 	heta=\frac{\sqrt{5}}{3}$[/tex], what is [tex]$\cos 	heta$[/tex]? Report your answer in simplest form. [tex]$\cos 	heta=[?]$[/tex]

KatieOG · Answer

4x-16=12 would be the equation. To solve: Add 16 to both sides. 4x=28 Divide by 4. x=7

TacoGod · Answer

Say it out loud and you should get your answer like that. 
 12 = 16 - 4x 
 Well, 16 - 4 already equals 12, so the x shouldn't have a value over 2. 
 The x must be a 1. 
 The equation would be 12 = 16 - 4 x 1. 
 Hope this helped.

TacoGod · Answer

The number is 7, which was found by setting up the equation 12 = 4 x − 16 and solving for x . 
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Given [tex]$\sin \theta=\frac{\sqrt{5}}{3}$[/tex], what is [tex]$\cos \theta$[/tex]? Report your answer in simplest form. [tex]$\cos \theta=[?]$[/tex]

Answer (3)

Given [tex]$\sin \theta=\frac{\sqrt{5}}{3}$[/tex], what is [tex]$\cos \theta$[/tex]? Report your answer in simplest form. [tex]$\cos \theta=[?]$[/tex]

Answer (3)

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