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In Mathematics / College | 2025-08-20

Solve for [tex]$h$[/tex].
[tex]
\begin{array}{l}
-3(h-18)=0 \\
h=\square
\end{array}
[/tex]

Asked by diego1712

Answer (2)

We can set the 2nd equation to y that way we have something to solve for { x 2 + x = y 3 x − 1 = 11 ​ First we solve our first equation by moving the one to the other side 3 x = 12 Then we divide by 3 on each side x = 4 So now we can plug 4 into the x's of the 2nd equation 4 2 + 4 = y 16 + 4 = y 20 = y

Answered by JohnoftheJungle | 2024-06-10

By solving the equation 3 x − 1 = 11 , we find x = 4 . Substituting this value into x 2 + x , we get 20 . Therefore, the final result is 20 .
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Answered by JohnoftheJungle | 2024-12-20

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