Let [tex]$f(x)=-x^2-5$[/tex] and [tex]$g(x)=3 x+2$[/tex]

Find and simplify [tex]$(g \circ f)(x)$[/tex].

A. [tex]$(g \circ f)(x)=9 x^2+12 x-1$[/tex]
B. [tex]$(g \circ f)(x)=-3 x^3-15 x+2$[/tex]
C. [tex]$(g \circ f)(x)=-3 x^2-13$[/tex]
D. [tex]$(g \circ f)(x)=-9 x^2-12 x-9$[/tex]

Question

Let [tex]$f(x)=-x^2-5$[/tex] and [tex]$g(x)=3 x+2$[/tex]

Find and simplify [tex]$(g \circ f)(x)$[/tex].

A. [tex]$(g \circ f)(x)=9 x^2+12 x-1$[/tex]
B. [tex]$(g \circ f)(x)=-3 x^3-15 x+2$[/tex]
C. [tex]$(g \circ f)(x)=-3 x^2-13$[/tex]
D. [tex]$(g \circ f)(x)=-9 x^2-12 x-9$[/tex]

Anonymous · Answer

Well, the total that went out is 8 3 ​ + 4 1 ​ = 8 3 + 2 ​ = 8 5 ​ That is, 8 5 ​ ∗ 24 = 15

jettelusa · Answer

1738 hey ;

Let [tex]$f(x)=-x^2-5$[/tex] and [tex]$g(x)=3 x+2$[/tex] Find and simplify [tex]$(g \circ f)(x)$[/tex]. A. [tex]$(g \circ f)(x)=9 x^2+12 x-1$[/tex] B. [tex]$(g \circ f)(x)=-3 x^3-15 x+2$[/tex] C. [tex]$(g \circ f)(x)=-3 x^2-13$[/tex] D. [tex]$(g \circ f)(x)=-9 x^2-12 x-9$[/tex]

Answer (2)

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Let [tex]$f(x)=-x^2-5$[/tex] and [tex]$g(x)=3 x+2$[/tex]

Find and simplify [tex]$(g \circ f)(x)$[/tex].

A. [tex]$(g \circ f)(x)=9 x^2+12 x-1$[/tex]
B. [tex]$(g \circ f)(x)=-3 x^3-15 x+2$[/tex]
C. [tex]$(g \circ f)(x)=-3 x^2-13$[/tex]
D. [tex]$(g \circ f)(x)=-9 x^2-12 x-9$[/tex]