Solve the equation below for [tex]$x$[/tex].
[tex]$32 x=96$[/tex]

A. [tex]$x=0.02$[/tex]
B. [tex]$x=0.2$[/tex]
C. [tex]$x=2$[/tex]
D. [tex]$x=20$[/tex]

you can work only as a farmer 15 hours per week 10x+5y>=150 => 10 x >= 150- 5y :5 => 2x >=30-y => 30-2x <= y x+y<= 25 => y>=30-2x y<=25-x

Answered by dannielle | 2024-06-10

x = nr. hrs working for a farmer; y = nr. hrs. babysitting; x + y <= 25; 10x + 5y >= 150
a) Solve the system => one of the solution is x =5; y = 20(babysitting) b) 10 + 12 =22 <= 25; 10*10 + 5*12 = 160 >=150.

Answered by crisforp | 2024-06-10

The system of inequalities that models the situation is 10x + 5y ≥ 150 and x + y ≤ 25, with both variables being non-negative. The combination of working 10 hours on the farm and 12 hours babysitting achieves an income of $160, which meets the goal of at least $150. Therefore, the student's plan is successful in reaching their financial target.
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Answered by dannielle | 2024-09-05