In Mathematics / High School | 2025-08-20

Name:
Lacky Borley
Period:
$\qquad$
Write each answer then mark it in the answer column. For each set of problems, there is one earra answer. Write the lenter of this answer
$\qquad$ in the corresponding box at the bottom of the page.

\begin{tabular}{|l|l|l|l|}
\hline \begin{tabular}{l}
1) $-5+2=C$
$7+(-3)=\searrow$ \\
$-4+(-6)=k$
\end{tabular} & \begin{tabular}{l}
Answers
(V) 4 (C) -3 \\
(A) -8 (K) -10
\end{tabular} & \begin{tabular}{l}
8) $-4-(-9)=$ U \\
$3-7=-4$ \\
$-6+15=$
\end{tabular} & \begin{tabular}{l}
Answers
(S) 9 (A) -4 \\
(1) 12
(U) 5
\end{tabular} \\
\hline \begin{tabular}{l}
2) $1+(-8)=5$
$-6+(-12)=J$ \\
$-2+9=-7$
\end{tabular} & \begin{tabular}{l}
Answers
(F) 7 (L) 13 \\
(U) -7 (I) -18
\end{tabular} & \begin{tabular}{l}
9)
$1-7=p$ \\
$-5-12=F$ \\
$-20+9=$
\end{tabular} & \begin{tabular}{l}
Answers
(A) 8 (I) -11 \\
(P) -6 (E) -17
\end{tabular} \\
\hline \begin{tabular}{l}
3) $-7+6= G$
$5+(-8)=N$ \\
$12+13=y$
\end{tabular} & \begin{tabular}{l}
Answers
(G) 1 (N) -3 \\
(Y) 25 (H) 18
\end{tabular} & \begin{tabular}{l}
10) $-4-3=$
$-4+3=0$ \\
$4-3=$
\end{tabular} & \begin{tabular}{l}
Answers
\begin{array}{ll}
(C) -7 & (R) 1 \\
(I) 7 & (O) -1
\end{array}
\end{tabular} \\
\hline & \begin{tabular}{l}
Answers
(D) 16 (T)- 8 \\
(R) -20 (B) -6
\end{tabular} & \begin{tabular}{l}
11) $-8+18=\backslash]$
$6-19=\zeta$
\end{tabular} & \begin{tabular}{l}
Answers
(N) 10 (W) -16 \\
(F) 18 (S) -13
\end{tabular} \\
\hline \begin{tabular}{l}
5) $4+(-9)=C$
$-7+(-15)=p$ \\
$-3+12=C$
\end{tabular} & \begin{tabular}{l}
Answers
(A) 14 (O) 9 \\
(P) -22 (C) -5
\end{tabular} & \begin{tabular}{l}
12) $11+(-2)=$
$-7-4=$
\\n$8-15=$
\end{tabular} & \begin{tabular}{l}
Answers
(I) 12 (E) 9 \\
(D) -7
(T) -11
\end{tabular} \\
\hline \begin{tabular}{l}
6) $16+(-8)=M$
$-5+20=t$ \\
$-6+6=$
\end{tabular} & \begin{tabular}{l}
Answers
(M) 8 (T) 15 \\
(S) -4 (W) 0
\end{tabular} & \begin{tabular}{l}
13) $-6+12=G$
$-99-(-99)=k$ \\
$3-5=P$
\end{tabular} & Answers
\begin{array}{ll}
(P) -2 & (G) 6 \\
(R) 0 & (B) -4
\end{array} \\
\hline \begin{tabular}{l}
7) $-13+(-4)=2$
$-7+2=F$ \\
$14+(-16)=E$
\end{tabular} & \begin{tabular}{l}
Answers
(F) -5 (Z) -17 \\
(E) -2 (O) 10
\end{tabular} & \begin{tabular}{l}
14) $-20+(-30)=M$
$70-40=1V$ \\
$40-70=t$
\end{tabular} & Answers
\begin{array}{l}
(Y) -50 (M) 50 \\
\begin{array}{ll}
(N) 30 & (I) -30
\end{array}
\end{array}
\end{tabular}
6) $16+(-8)=M$
$-5+20=$
$-6+6=$
$-6+6=$
$6+6=$
7)
\begin{tabular}{l}
$-13+(-4)=2$
$-7+2=F$ \\
$14+(-16)=F$
\end{tabular}

Answers
(F) -5
(Z) -17
(O) 10
14) $-20+(-30)=M$

Answers
(Y) -50
(M) 50
(T) -30

\begin{tabular}{|c|c|c|c|c|c|c|c|c|c|c|c|c|c|}
\hline 8 & 4 & 11 & 1 & 6 & 9 & 14 & 7 & 10 & 3 & 13 & 5 & 2 & 12 \\
\hline
\end{tabular}

Asked by lacey53397