Consider circle N with radius 30 cm and [tex]$\theta=\frac{\pi}{6}$[/tex] radians.
What is the approximate length of minor arc LM? Round to the nearest tenth of a centimeter.
A. 12.4 centimeters
B. 15.7 centimeters
C. 31.4 centimeters
D. 36.7 centimeters
Asked by kashmir3166
Answer (1)
The correct answer here is A because it asks to prove congruence. Since we know line ST is the BISECTOR of PR, we know that Q is the middle point and indeed PQ and RQ are congruent lines.