The table shows ordered pairs of the function [tex]y=8-2 x[/tex]. What is the value of [tex]y[/tex] when [tex]x=8[/tex]?

\begin{tabular}{|l|l|}
\hline [tex]x[/tex] & [tex]y[/tex] \
\hline -3 & 14 \
\hline -1 & 10 \
\hline 1 & 6 \
\hline 4 & 0 \
\hline 8 & ? \
\hline 10 & -12 \
\hline
\end{tabular}

Question

The table shows ordered pairs of the function [tex]y=8-2 x[/tex]. What is the value of [tex]y[/tex] when [tex]x=8[/tex]? 
 
\begin{tabular}{|l|l|} 
\hline [tex]x[/tex] &amp; [tex]y[/tex] \ 
\hline -3 &amp; 14 \ 
\hline -1 &amp; 10 \ 
\hline 1 &amp; 6 \ 
\hline 4 &amp; 0 \ 
\hline 8 &amp; ? \ 
\hline 10 &amp; -12 \ 
\hline 
\end{tabular}

jlorhea · Answer

the probability is a fraction. all possible outcomes / number of items so 8/11 is the probablity of finding a number higher than 3 out of 11 could also be written as: 8/11 8:11 .73 73 percent

jlorhea · Answer

The probability that both random numbers generated are greater than three is 121 64 ​ , which is approximately 52.89%. This means there is a little over a 50% chance that both numbers will fit this criterion. Understanding the basic principle of calculating probabilities helps in assessing such scenarios effectively. 
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