If [tex]f(x)=x^2-2x[/tex] and [tex]g(x)=6x+4[/tex], for which value of [tex]x[/tex] does [tex](f+g)(x)=0[/tex]?
Answer (3)
In order to subtract two fractions, they need to have a common denominator which would be 12, so you need to change all the denominators to 12. 7/12 is still 7/12 1/6 is multiplied by 2/2 to become 2/12. Then you can subtract. 7/12 - 2/12 = 5/12 So the simplest form would be 5/12
7/12-1/6=7/12-2/12=5/12
To subtract 12 7 and 6 1 , first change 6 1 to 12 2 . Then subtract: 12 7 − 12 2 = 12 5 , which is the simplest form.
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