The seismic activity density of a region is the ratio of the number of earthquakes during a given time span to the land area affected. The table shows the land area and seismic activity density.
\begin{tabular}{|r|r|r|}
\hline & Land Area $\left( mi ^2\right)$ & Seismic Activity Density \\
\hline State A & 163,696 & 0.0299 \\
\hline State B & 10,931 & 0.1402 \\
\hline
\end{tabular}
Which statement about the number of earthquakes the states had for the given time span is true?
A. State $A$ had approximately 1,533 more earthquakes than State B.
B. State $B$ had approximately 1,533 more earthquakes than State A.
C. State $A$ had approximately 3,362 more earthquakes than State B.
D. State $B$ had approximately 3,362 more earthquakes than State A.
Answer (3)
g = number of girls; b= number of boys we know that: g= 6+2b and that: g+b= 156 kids in total so we may write g+b=(6+2b)+b=6+3b but g+b= 156 so 6+3b = 156 => 3b= 156-6=150 => b=150/3=50 => b = 50 (number of boys) g= 6+2b= 6+2 x 50= 106 => g =106 (number of girls)
To find the number of boys and girls at the camp, use the 5-d process. With the given information, we can set up equations and solve for the values of B and G. ;
In total, there are 50 boys and 106 girls at the Cyber summer camp. This was calculated by setting up equations based on the given relationships between the number of boys and girls. Using substitution, we found the values of both variables based on the total number of students.
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