Operate the simplification steps for the expression below using the properties of rational exponents.
$\sqrt[4]{567 x^9 y^{11}}$
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| ------------------------------------- | - |
| $\left(56 b^9 y^{11}\right)^{\frac{1}{6}}$ | |
| $3^1 \cdot 7^{\frac{1}{4}} \cdot x^2 \cdot x^{\frac{1}{4}} \cdot y^2 \cdot y^{\frac{3}{4}}$ | |
| $(81)^{\frac{1}{4}} \cdot(7)^{\frac{1}{4}} \cdot x^{\left(\frac{3}{4}+\frac{1}{4}\right)} \cdot y^{\left(\frac{3}{4}+\frac{3}{4}\right)}$ | |
| $(81 \cdot 7)^{\frac{1}{2}} \cdot x^{\frac{2}{4}} \cdot y^{\frac{11}{4}}$ | |
| $3 x^2 y^2 \sqrt[4]{7 x y^3}$ | |
| $3 x^2 y^2 \cdot\left(7 x y^3\right)^{\frac{1}{6}}$ | |
| $3 \cdot x^2 \cdot y^2 \cdot\left(7^{\frac{1}{4}} \cdot x^{\frac{1}{4}} \cdot y^{\frac{3}{4}}\right)$ | |
| $\left(3^4\right)^{\frac{1}{4}} \cdot 7^{\frac{1}{4}} \cdot x^{\left(2+\frac{1}{4}\right)} \cdot y^{\left(2+\frac{1}{4}\right)}$ | 1 |
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Answer (3)
6 days each week and 8 hours each day so total hours = (6x8) = 48 hours.
he earned $360 in a week it means he earn that much money working 48 hours so he paid in one hour is (360/48) = $7.5 (ans)
$7.50 because 6x8 equals 48 and 360 divided by 360 equals $7.50
Andrew worked 48 hours in a week and earned $360. Dividing his total earnings by the total hours gives an hourly wage of $7.50. Therefore, he was paid $7.50 for each hour of work.
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