A compound with molar mass 159 was found to contain 39.62% Copper and 20.13% Sulfur. Suggest the molecular formula. Given atomic masses: Cu = 63, S = 32, and O = 16.

Question

jsimpson11000 · Answer

Cu .3962 * 159 = 62.99 
 S .2013 * 159 = 32 remainder is O 100% - 39.62 - 20.13 = 40.25% 
 O .4025 * 159 = 63.99 
 Now divide by the respective molar weights 
 Cu = 62.99/63 = ~1 
 S = 32/32 = 1 
 O = 63.99/16 =~ 4 so the **formula would be Cu S O 4 ** ;

jsimpson11000 · Answer

The compound has a molecular formula of CuS 4 ​ , as determined by calculating the percentage composition of the elements and establishing their mole ratio. The empirical formula matches the given molar mass of 159 g/mol. Thus, the final molecular formula is CuS 4 ​ . 
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A compound with molar mass 159 was found to contain 39.62% Copper and 20.13% Sulfur. Suggest the molecular formula. Given atomic masses: Cu = 63, S = 32, and O = 16.

Answer (2)

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