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In Mathematics / College | 2025-07-07

Simplify each expression, using exact forms.
a) [tex]$\sqrt{128}-\sqrt{32}=[/tex]

b) [tex]$\sqrt[3]{2058}+\sqrt[3]{384}=[/tex]

c) [tex]$\frac{1}{8} \sqrt[4]{24576}+\frac{1}{2} \sqrt[4]{96}=[/tex]

NOTE: To input [tex]$a \sqrt{b}$[/tex], type "a sqrt(b)". To input [tex]$a \sqrt[b]{c}$[/tex], type "a root(b)(c)".

Asked by lucidd713

Answer (2)

Simplify 128 ​ and 32 ​ to 8 2 ​ and 4 2 ​ , respectively, then subtract to get 4 2 ​ .
Simplify 3 2058 ​ and 3 384 ​ to 7 3 6 ​ and 4 3 6 ​ , respectively, then add to get 11 3 6 ​ .
Simplify 4 24576 ​ and 4 96 ​ to 8 4 6 ​ and 2 4 6 ​ , respectively, then compute 8 1 ​ ( 8 4 6 ​ ) + 2 1 ​ ( 2 4 6 ​ ) to get 2 4 6 ​ .

Explanation

Problem Analysis We are asked to simplify three expressions involving radicals. We will simplify each radical by finding the largest perfect square, cube, or fourth power factors, and then combine like terms.

Simplifying a) a) We have 128 ​ − 32 ​ .
We simplify 128 ​ as follows: 128 ​ = 64 × 2 ​ = 64 ​ × 2 ​ = 8 2 ​ We simplify 32 ​ as follows: 32 ​ = 16 × 2 ​ = 16 ​ × 2 ​ = 4 2 ​ Therefore, 128 ​ − 32 ​ = 8 2 ​ − 4 2 ​ = ( 8 − 4 ) 2 ​ = 4 2 ​

Simplifying b) b) We have 3 2058 ​ + 3 384 ​ .
We simplify 3 2058 ​ as follows: 3 2058 ​ = 3 343 × 6 ​ = 3 343 ​ × 3 6 ​ = 7 3 6 ​ We simplify 3 384 ​ as follows: 3 384 ​ = 3 64 × 6 ​ = 3 64 ​ × 3 6 ​ = 4 3 6 ​ Therefore, 3 2058 ​ + 3 384 ​ = 7 3 6 ​ + 4 3 6 ​ = ( 7 + 4 ) 3 6 ​ = 11 3 6 ​

Simplifying c) c) We have 8 1 ​ 4 24576 ​ + 2 1 ​ 4 96 ​ .
We simplify 4 24576 ​ as follows: 4 24576 ​ = 4 4096 × 6 ​ = 4 4096 ​ × 4 6 ​ = 8 4 6 ​ We simplify 4 96 ​ as follows: 4 96 ​ = 4 16 × 6 ​ = 4 16 ​ × 4 6 ​ = 2 4 6 ​ Therefore, 8 1 ​ 4 24576 ​ + 2 1 ​ 4 96 ​ = 8 1 ​ ( 8 4 6 ​ ) + 2 1 ​ ( 2 4 6 ​ ) = 4 6 ​ + 4 6 ​ = 2 4 6 ​

Final Answer a) 128 ​ − 32 ​ = 4 2 ​ b) 3 2058 ​ + 3 384 ​ = 11 3 6 ​ c) 8 1 ​ 4 24576 ​ + 2 1 ​ 4 96 ​ = 2 4 6 ​


Examples
Radicals are used in various fields, including engineering and physics. For example, when calculating the impedance of an AC circuit, you often encounter expressions involving square roots. Simplifying these expressions allows engineers to easily determine the circuit's behavior and design appropriate components. Similarly, in physics, radicals appear in formulas for energy, momentum, and other physical quantities, making their simplification crucial for accurate calculations and predictions.

Answered by GinnyAnswer | 2025-07-07

The simplified results for the expressions are: a) 4 2 ​ , b) 11 3 6 ​ , and c) 2 4 6 ​ . Each radical was simplified by finding perfect factors and combining like terms. This process involves breaking down the numbers under the radicals into their prime factors and recognizing perfect squares, cubes, and fourth powers.
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Answered by Anonymous | 2025-07-16