One boat travels downstream 30 km and returns upstream. If the downstream speed is 6km/h faster than the upstream speed, and the round trip took 5 hours, find the speeds.

Question

Anonymous · Answer

The upstream speed of the boat is approximately 6.68 km/h, while the downstream speed is approximately 12.68 km/h. These speeds are calculated based on the total time for the round trip being 5 hours. The speeds differ by 6 km/h, as stated in the question. 
 ;

anant194 · Answer

Let the upstream speed be x kilometers per hour. The downstream speed is then x plus 6 kilometers per hour. The boat travels 30 kilometers each way, and the total time for the round trip is 5 hours. 
 Using the formula time equals distance divided by speed, the total time is: 
 30 divided by (x plus 6) plus 30 divided by x equals 5. 
 Solving this equation, the upstream speed is approximately 9.71 kilometers per hour, and the downstream speed is approximately 15.71 kilometers per hour.

One boat travels downstream 30 km and returns upstream. If the downstream speed is 6km/h faster than the upstream speed, and the round trip took 5 hours, find the speeds.

Answer (2)

Related Questions in Mathematics

📝 Answered - Select the correct answer. Which equation is equivalent to the given equation? [tex]$x^2-6 x=8$[/tex] A. [tex]$(x-6)^2=44$[/tex] B. [tex]$(x-3)^2=17$[/tex] C. [tex]$(x-6)^2=20$[/tex] D. [tex]$(x-3)^2=14$[/tex]

📝 Answered - Which phrase best describes the translation from the graph [tex]y=6 x^2[/tex] to the graph of [tex]y=6(x+1)^2[/tex]? A. 6 units left B. 6 units right C. 1 unit left D. 1 unit right

📝 Answered - What expression is equivalent to [tex]$\left(5 z^2+3 z+2\right)^2$[/tex] ? A. [tex]$5 z^4+3 z^2+4$[/tex] B. [tex]$5 z^4+9 z^2+4$[/tex] C. [tex]$25 z^4+30 z^3+19 z^2+12 z+4$[/tex] D. [tex]$25 z^4+30 z^3+29 z^2+12 z+4$[/tex]

📝 Answered - The graph of [tex]y=\frac{5}{4} x+1[/tex] is shown below. The coordinate ([tex]0, y[/tex]) is a solution of the equation. Given the [tex]x[/tex]-value of 0, what is the value of the [tex]y[/tex]-coordinate for the coordinate ([tex]0, y[/tex])? [tex]y=[/tex] [blank]

📝 Answered - If [tex]f(-2)=0[/tex], what are all the factors of the function [tex]f(x)=x^3-2 x^2-68 x-120[/tex]? Use the Remainder Theorem. A. [tex](x+2)(x+60)[/tex] B. [tex](x-2)(x-60)[/tex] C. [tex](x-10)(x+2)(x+6)[/tex] D. [tex](x+10)(x-2)(x-6)[/tex]