A tank leaks water at a constant rate. After 3 hours it has 280L, and after 7 hours, 120L. Find the original amount and rate of leakage.
Answer (2)
The original amount of water in the tank was 400L, and the rate of leakage is 40L per hour.
;
Constant rate is then
(280 L - 120 L ) / (7 - 3) hr = 40 L per hour
It started with 3 hrs * 40 L / hr + 280 L =** 400 iters ** ;
