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In Mathematics / College | 2025-07-05

Consider the function [tex]f(x)=8 x+2 x^{-1}[/tex]. For this function there are four important intervals: [tex](-\infty, A][/tex], [tex][A, B)[/tex], [tex](B, C][/tex], and [tex][C, \infty)[/tex] where [tex]A[/tex], and [tex]C[/tex] are the critical numbers and the function is not defined at [tex]B[/tex].
Find [tex]A[/tex], [tex]B[/tex], and [tex]C[/tex].

Asked by nortoncampbel

Answer (1)

Find the derivative of the function: f ′ ( x ) = 8 − x 2 2 ​ .
Set the derivative to zero and solve for x to find the critical points: x = ± 2 1 ​ .
Determine where the function is undefined: x = 0 .
Assign the values to A , B , and C such that A < B < C : A = − 2 1 ​ , B = 0 , C = 2 1 ​ .

A = − 2 1 ​ , B = 0 , C = 2 1 ​ ​
Explanation

Problem Analysis We are given the function f ( x ) = 8 x + 2 x − 1 and asked to find the critical numbers A and C , and the point B where the function is not defined, such that the intervals are ( − ∞ , A ] , [ A , B ) , ( B , C ] , and [ C , ∞ ) .

Finding the Derivative First, we need to find the critical numbers by taking the derivative of f ( x ) and setting it equal to zero. The derivative of f ( x ) is f ′ ( x ) = d x d ​ ( 8 x + 2 x − 1 ) = 8 − 2 x − 2 = 8 − x 2 2 ​ .

Finding Critical Numbers Now, we set f ′ ( x ) = 0 and solve for x :
8 − x 2 2 ​ = 0 ⇒ 8 = x 2 2 ​ ⇒ x 2 = 8 2 ​ = 4 1 ​ ⇒ x = ± 2 1 ​ . Thus, the critical numbers are x = − 2 1 ​ and x = 2 1 ​ .

Finding Undefined Point Next, we need to find where the function f ( x ) is not defined. Since f ( x ) = 8 x + x 2 ​ , the function is not defined when x = 0 .

Assigning Values We are given that A , and C are the critical numbers and the function is not defined at B . Also, we know that A < B < C . Therefore, we have A = − 2 1 ​ , B = 0 , and C = 2 1 ​ .

Final Answer Thus, we have found that A = − 2 1 ​ , B = 0 , and C = 2 1 ​ .


Examples
Understanding critical points and intervals where a function is defined is crucial in optimization problems. For example, if you're designing a container to minimize surface area for a given volume, you'd use calculus to find critical dimensions. Knowing where the function is undefined helps avoid physically impossible solutions, ensuring your design is both mathematically optimal and practically feasible.

Answered by GinnyAnswer | 2025-07-05