GuideFoot - Learn Together, Grow Smarter. Logo

In Mathematics / College | 2025-07-05

Solve for $x$: $-2.863 .98 - 0.8y = -2.86$

Asked by frankiegonzalex91

Answer (2)

To solve for y in the equation − 2.863 × 0.98 − 0.8 y = − 2.86 , we first calculate the product and then isolate y to find that y ≈ 0.067825 . This solution illustrates a common algebraic technique of isolating variables through addition and division. Understanding this method is essential for solving many algebra problems.
;

Answered by Anonymous | 2025-07-05

First, calculate the product: − 2.863 × 0.98 = − 2.80574 .
Then, rewrite the equation: − 2.80574 − 0.8 y = − 2.86 .
Isolate the y term: − 0.8 y = − 2.86 + 2.80574 = − 0.05426 .
Finally, solve for y: y = − 0.8 − 0.05426 ​ = 0.067825 . The final answer is 0.067825 ​ .

Explanation

Problem Analysis We are given the equation − 2.863 × 0.98 − 0.8 y = − 2.86 and we want to solve for y .

Calculating the Product First, we need to calculate the product of − 2.863 and 0.98 . The result of this multiplication is − 2.80574 . So, the equation becomes: − 2.80574 − 0.8 y = − 2.86

Isolating the y term Next, we want to isolate the term with y . To do this, we add 2.80574 to both sides of the equation: − 0.8 y = − 2.86 + 2.80574

Simplifying the Equation Now, we simplify the right side of the equation: − 0.8 y = − 0.05426

Solving for y Finally, to solve for y , we divide both sides of the equation by − 0.8 :
y = − 0.8 − 0.05426 ​ = 0.067825

Final Answer Therefore, the solution for y is approximately 0.067825 .


Examples
Imagine you're adjusting a recipe where a small change in one ingredient affects the others. Solving for 'y' in this equation is like figuring out how much of one ingredient you need to add or subtract to keep the recipe balanced after changing another ingredient. This type of problem helps in scenarios like adjusting chemical mixtures, calibrating instruments, or fine-tuning any process where variables are interconnected. Understanding how to isolate and solve for a variable allows for precise adjustments and optimal outcomes.

Answered by GinnyAnswer | 2025-07-05