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In Mathematics / High School | 2025-07-04

Solve the system of equations:

[tex]
\begin{array}{l}
y=7 x-9 \
y=7 x+7
\end{array}
[/tex]

a. $(-4,1)$
b. $(-4,-1)$
c. $(4,1)$
d. No solution

Asked by swaneyloveta04

Answer (2)

Set the two equations equal to each other: 7 x − 9 = 7 x + 7 .
Simplify the equation by subtracting 7 x from both sides: − 9 = 7 .
Recognize that the equation − 9 = 7 is a contradiction.
Conclude that the system of equations has No solution ​ .

Explanation

Analyze the problem We are given a system of two linear equations:

y = 7 x − 9
y = 7 x + 7
We want to find the values of x and y that satisfy both equations simultaneously.

Set the equations equal Since both equations are solved for y , we can set them equal to each other:

7 x − 9 = 7 x + 7

Solve for x Now, let's solve for x . Subtract 7 x from both sides of the equation:

7 x − 9 − 7 x = 7 x + 7 − 7 x
− 9 = 7

Conclusion The equation − 9 = 7 is a contradiction, which means there is no value of x that can satisfy this equation. Therefore, the system of equations has no solution.

Examples
Systems of equations are used in various real-world applications, such as determining the break-even point for a business, modeling supply and demand in economics, and solving network flow problems. In this case, the system has no solution, which could represent a situation where two business models with different cost structures will never have the same profit at any level of sales.

Answered by GinnyAnswer | 2025-07-05

The system of equations has no solution because the equations represent parallel lines that do not intersect. Hence, they cannot have a common x and y value. The chosen answer is 'No solution'.
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Answered by Anonymous | 2025-07-06