GuideFoot - Learn Together, Grow Smarter. Logo

In Mathematics / College | 2025-07-04

A hyperbola centered at the origin has a vertex at $(0,-40)$ and a focus at $(0,41)$.
\begin{tabular}{|l|l|}
\hline Vertices: (-a,0), (a,0) & Vertices: ( $0,-a),(0, a)$ \\
\hline Foci: (-c,0),(c,0) & Focii $(0,-c),(0, c)$ \\
\hline Asymptotes: $y= \pm \frac{b}{a} x$ & Asymptotes: $y= \pm \frac{a}{b} x$ \\
\hline Directrices: $x= \pm \frac{a^2}{c}$ & Directrices: $y= \pm \frac{a^2}{c}$ \\
\hline Standard Equation: $\frac{x^2}{a^2}-\frac{y^2}{b^2}=1$ & Standard Equation: $\frac{y^2}{a^2}-\frac{x^2}{b^2}=1$ \\
\hline
\end{tabular}

Which are the equations of the asymptotes?

Asked by Mackeila

Answer (2)

Identifies the hyperbola's parameters: vertex ( 0 , − 40 ) implies a = 40 , focus ( 0 , 41 ) implies c = 41 .
Applies the hyperbola relationship c 2 = a 2 + b 2 to find b 2 = 4 1 2 − 4 0 2 = 81 , thus b = 9 .
Uses the formula for asymptotes y = ± b a ​ x with a = 40 and b = 9 .
Concludes that the equations of the asymptotes are y = ± 9 40 ​ x ​ .

Explanation

Analyze the problem and given data We are given a hyperbola centered at the origin with a vertex at ( 0 , − 40 ) and a focus at ( 0 , 41 ) . We need to find the equations of the asymptotes. From the table provided, since the vertices and foci are on the y-axis, the standard equation of the hyperbola is of the form a 2 y 2 ​ − b 2 x 2 ​ = 1 , and the asymptotes are given by y = ± b a ​ x .

Find the values of a and c Since the vertex is at ( 0 , − 40 ) , we have a = 40 . Since the focus is at ( 0 , 41 ) , we have c = 41 . For a hyperbola, the relationship between a , b , and c is given by c 2 = a 2 + b 2 .

Calculate b^2 Substitute the values of a and c into the equation c 2 = a 2 + b 2 to find b 2 :


4 1 2 = 4 0 2 + b 2
Solve for b 2 :
b 2 = 4 1 2 − 4 0 2 = 1681 − 1600 = 81

Calculate b Therefore, b = 81 ​ = 9 .

Find the equations of the asymptotes The equations of the asymptotes are y = ± b a ​ x = ± 9 40 ​ x . Thus, the equations of the asymptotes are y = 9 40 ​ x and y = − 9 40 ​ x .


Examples
Understanding hyperbolas and their asymptotes is crucial in various fields, such as physics and engineering. For instance, the trajectory of a comet as it approaches and recedes from the sun can be modeled as a hyperbola, with the asymptotes providing an approximation of the comet's path far from the sun. Similarly, in radio navigation systems like LORAN, hyperbolas are used to determine the location of a receiver based on the time difference of arrival of signals from different transmitters. The asymptotes help in understanding the boundaries of the possible locations.

Answered by GinnyAnswer | 2025-07-04

The equations of the asymptotes for the hyperbola centered at the origin with a vertex at (0, -40) and a focus at (0, 41) are y = 9 40 ​ x and y = − 9 40 ​ x . To derive these equations, we identified the values of a and b and utilized the formula for asymptotes of a hyperbola with a vertical transverse axis.
;

Answered by Anonymous | 2025-07-06