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In Mathematics / High School | 2025-07-04

What are the potential solutions of: log4x+log4(x+6)=2

x=-2 and x=-8
x=-2 and x=8
x=2 and x=-8
x=2 and x=8

Asked by 558033

Answer (2)

The valid solution to the equation lo g 4 ​ x + lo g 4 ​ ( x + 6 ) = 2 is x = 2 . The solution x = − 8 is not valid due to the logarithm being undefined for non-positive numbers. Therefore, the answer is x = 2.
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Answered by Anonymous | 2025-07-04

C ;

Answered by jimrgrant1 | 2025-07-04

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