Calculate the discriminant Δ = b 2 − 4 a c with a = 1 , b = − 16 , and c = 64 .
Find that Δ = ( − 16 ) 2 − 4 ( 1 ) ( 64 ) = 256 − 256 = 0 .
Since Δ = 0 , the equation has one real solution.
Therefore, the quadratic equation x 2 − 16 x + 64 = 0 has one solution: The equation has one solution.
Explanation
Understanding the Problem We are given the quadratic equation x 2 − 16 x + 64 = 0 . Our goal is to determine how many solutions this equation has. To do this, we will use the discriminant.
Identifying Coefficients and the Discriminant The discriminant, denoted as Δ , is given by the formula Δ = b 2 − 4 a c , where a , b , and c are the coefficients of the quadratic equation a x 2 + b x + c = 0 . In our case, a = 1 , b = − 16 , and c = 64 .
Calculating the Discriminant Now, we calculate the discriminant: Δ = ( − 16 ) 2 − 4 ( 1 ) ( 64 ) = 256 − 256 = 0
Interpreting the Discriminant The discriminant tells us about the nature of the solutions:
If 0"> Δ > 0 , the equation has two distinct real solutions.
If Δ = 0 , the equation has one real solution (a repeated root).
If Δ < 0 , the equation has no real solutions.
Determining the Number of Solutions Since Δ = 0 , the quadratic equation has one real solution (a repeated root).
Final Answer Therefore, the correct statement is: The equation has one solution.
Examples
Quadratic equations are used in various real-life scenarios, such as calculating the trajectory of a projectile, determining the dimensions of a rectangular area given its area and perimeter, and modeling the growth or decay of populations. For example, if you want to build a rectangular garden with an area of 64 square meters and you have 16 meters of fencing material, you can use a quadratic equation to find the dimensions of the garden that maximize the enclosed area. Understanding the number of solutions helps in determining if a feasible solution exists for the given constraints.