The temperature measured in Kelvin (K) is the temperature measured in Celsius ($C$) increased by 273.15. This can be modeled by the equation $K=C+$ 273.15.
When solved for $C$, the equation is
A. $C=K-273.15$
B. $C=273.15-K$
C. $C=K+273.15$
D. $C=273.15 K$
Answer (1)
Start with the equation K = C + 273.15 .
Subtract 273.15 from both sides to isolate C : C = K − 273.15 .
Compare the result with the given options.
The correct equation is C = K − 273.15 .
Explanation
Understanding the equation We are given the equation that relates Kelvin (K) and Celsius (C): K = C + 273.15 We need to solve this equation for C . This means we want to isolate C on one side of the equation.
Isolating C To isolate C , we need to subtract 273.15 from both sides of the equation: K − 273.15 = C + 273.15 − 273.15 This simplifies to: K − 273.15 = C So, we have: C = K − 273.15
Comparing with the options Now, we compare our solution with the given options:
C = K − 273.15 - This matches our solution. C = 273.15 − K - This is incorrect. C = K + 273.15 - This is incorrect. C = 273.15 K - This is incorrect.
Examples
Understanding the relationship between Kelvin and Celsius is crucial in many scientific applications. For example, in chemistry, reaction rates and equilibrium constants are often temperature-dependent, and using the correct temperature scale is essential for accurate calculations. Similarly, in meteorology, temperature measurements are used to predict weather patterns, and converting between Kelvin and Celsius allows for consistent data analysis across different regions and measurement systems. Imagine you're a chef following a recipe that specifies the oven temperature in Celsius, but your oven only displays Fahrenheit. Converting to Kelvin first can help ensure you get the precise temperature needed for a perfect bake, highlighting the importance of temperature conversions in everyday applications.
