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In Mathematics / College | 2025-07-04

Find the equation of the tangent to the given curve at the indicated point.
(a) [tex]y=x^3+x^2+1[/tex]
(1,3)

Asked by amonkibet854

Answer (2)

To find the tangent line to the curve y = x 3 + x 2 + 1 at the point ( 1 , 3 ) , we calculate the derivative to find the slope, which is 5 at this point. Using the point-slope form of a line, the equation of the tangent line is y = 5 x − 2 .
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Answered by Anonymous | 2025-07-04

Find the derivative of the function: d x d y ​ = 3 x 2 + 2 x .
Evaluate the derivative at x = 1 to find the slope: m = 5 .
Use the point-slope form of a line: y − 3 = 5 ( x − 1 ) .
Simplify to find the equation of the tangent line: y = 5 x − 2 ​ .

Explanation

Problem Analysis We are given the curve y = x 3 + x 2 + 1 and the point ( 1 , 3 ) . Our goal is to find the equation of the tangent line to the curve at this point.

Finding the Derivative First, we need to find the derivative of the function y = x 3 + x 2 + 1 with respect to x . This will give us the slope of the tangent line at any point on the curve. Using the power rule, we find the derivative to be: d x d y ​ = 3 x 2 + 2 x

Evaluating the Derivative at x=1 Next, we need to evaluate the derivative at x = 1 to find the slope of the tangent line at the point ( 1 , 3 ) .
m = d x d y ​ ∣ x = 1 ​ = 3 ( 1 ) 2 + 2 ( 1 ) = 3 + 2 = 5 So, the slope of the tangent line at the point ( 1 , 3 ) is 5 .

Finding the Tangent Line Equation Now, we use the point-slope form of a line, which is given by y − y 1 ​ = m ( x − x 1 ​ ) , where ( x 1 ​ , y 1 ​ ) = ( 1 , 3 ) and m = 5 . Plugging in these values, we get: y − 3 = 5 ( x − 1 ) y − 3 = 5 x − 5 y = 5 x − 5 + 3 y = 5 x − 2

Final Answer Therefore, the equation of the tangent line to the curve y = x 3 + x 2 + 1 at the point ( 1 , 3 ) is y = 5 x − 2 .


Examples
Understanding tangent lines is crucial in various fields. For instance, in physics, the tangent line to a position-time curve gives the instantaneous velocity of an object. In economics, it can represent the marginal cost or revenue at a particular production level. Moreover, tangent lines are fundamental in optimization problems, helping to find maximum and minimum values of functions, which are essential in engineering and business applications.

Answered by GinnyAnswer | 2025-07-04