Work out these sums in your notebook:
$6 \overline{)49}$
$8 \overline{)58}$
$9 \overline{)83}$
$10 \overline{)3}$
$9 \overline{)74}$
$8 \overline{)66}$
$8 \overline{)75}$
$4 \overline{)33}$
$9 \overline{)89}$
$7 \overline{)54}$
Answer (1)
Divide 49 by 6: 49 = 6 × 8 + 1 , so the quotient is 8 and the remainder is 1.
Divide 58 by 8: 58 = 8 × 7 + 2 , so the quotient is 7 and the remainder is 2.
Divide 83 by 9: 83 = 9 × 9 + 2 , so the quotient is 9 and the remainder is 2.
Divide 3 by 10: 3 = 10 × 0 + 3 , so the quotient is 0 and the remainder is 3.
Divide 74 by 9: 74 = 9 × 8 + 2 , so the quotient is 8 and the remainder is 2.
Divide 66 by 8: 66 = 8 × 8 + 2 , so the quotient is 8 and the remainder is 2.
Divide 75 by 8: 75 = 8 × 9 + 3 , so the quotient is 9 and the remainder is 3.
Divide 33 by 4: 33 = 4 × 8 + 1 , so the quotient is 8 and the remainder is 1.
Divide 89 by 9: 89 = 9 × 9 + 8 , so the quotient is 9 and the remainder is 8.
Divide 54 by 7: 54 = 7 × 7 + 5 , so the quotient is 7 and the remainder is 5.
Explanation
Problem Overview We are given a series of division problems and asked to find the quotient and remainder for each. Let's tackle them one by one!
Solving 6 | 49 For the first problem, we have 6 v er t 49 . We need to find the largest multiple of 6 that is less than or equal to 49.
Result of 6 | 49 We know that 6 v er t 8 = 48 , so 49 = 6 v er t 8 + 1 . Thus, the quotient is 8 and the remainder is 1.
Solving 8 | 58 Next, we have 8 v er t 58 . We need to find the largest multiple of 8 that is less than or equal to 58.
Result of 8 | 58 We know that 8 v er t 7 = 56 , so 58 = 8 v er t 7 + 2 . Thus, the quotient is 7 and the remainder is 2.
Solving 9 | 83 Now, let's solve 9 v er t 83 . We need to find the largest multiple of 9 that is less than or equal to 83.
Result of 9 | 83 We know that 9 v er t 9 = 81 , so 83 = 9 v er t 9 + 2 . Thus, the quotient is 9 and the remainder is 2.
Solving 10 | 3 Next, we have 10 v er t 3 . We need to find the largest multiple of 10 that is less than or equal to 3.
Result of 10 | 3 Since 10 is greater than 3, the quotient is 0 and the remainder is 3. So, 3 = 10 v er t 0 + 3 .
Solving 9 | 74 Now, let's solve 9 v er t 74 . We need to find the largest multiple of 9 that is less than or equal to 74.
Result of 9 | 74 We know that 9 v er t 8 = 72 , so 74 = 9 v er t 8 + 2 . Thus, the quotient is 8 and the remainder is 2.
Solving 8 | 66 Next, we have 8 v er t 66 . We need to find the largest multiple of 8 that is less than or equal to 66.
Result of 8 | 66 We know that 8 v er t 8 = 64 , so 66 = 8 v er t 8 + 2 . Thus, the quotient is 8 and the remainder is 2.
Solving 8 | 75 Now, let's solve 8 v er t 75 . We need to find the largest multiple of 8 that is less than or equal to 75.
Result of 8 | 75 We know that 8 v er t 9 = 72 , so 75 = 8 v er t 9 + 3 . Thus, the quotient is 9 and the remainder is 3.
Solving 4 | 33 Next, we have 4 v er t 33 . We need to find the largest multiple of 4 that is less than or equal to 33.
Result of 4 | 33 We know that 4 v er t 8 = 32 , so 33 = 4 v er t 8 + 1 . Thus, the quotient is 8 and the remainder is 1.
Solving 9 | 89 Now, let's solve 9 v er t 89 . We need to find the largest multiple of 9 that is less than or equal to 89.
Result of 9 | 89 We know that 9 v er t 9 = 81 , so 89 = 9 v er t 9 + 8 . Thus, the quotient is 9 and the remainder is 8.
Solving 7 | 54 Finally, we have 7 v er t 54 . We need to find the largest multiple of 7 that is less than or equal to 54.
Result of 7 | 54 We know that 7 v er t 7 = 49 , so 54 = 7 v er t 7 + 5 . Thus, the quotient is 7 and the remainder is 5.
Final Answer In summary: 6 v er t 49 = 8 with a remainder of 1. 8 v er t 58 = 7 with a remainder of 2. 9 v er t 83 = 9 with a remainder of 2. 10 v er t 3 = 0 with a remainder of 3. 9 v er t 74 = 8 with a remainder of 2. 8 v er t 66 = 8 with a remainder of 2. 8 v er t 75 = 9 with a remainder of 3. 4 v er t 33 = 8 with a remainder of 1. 9 v er t 89 = 9 with a remainder of 8. 7 v er t 54 = 7 with a remainder of 5.
Examples
Division is a fundamental operation in mathematics that helps us understand how quantities can be split into equal parts. In real life, division is used in numerous scenarios, such as splitting a pizza among friends, calculating the average speed of a car, or determining how many items can be purchased with a certain amount of money. For instance, if you have 24 slices of pizza and want to divide them equally among 6 friends, you would perform the division 24 ÷ 6 = 4 , meaning each friend gets 4 slices.
