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In Mathematics / High School | 2025-07-03

Find the sum of the following geometric series: [tex]$\sqrt{2}+\frac{1}{\sqrt{2}}+\frac{1}{2 \sqrt{2}}+\ldots \text { to } 8 \text { term }$[/tex]

Asked by kisun5271

Answer (2)

The sum of the given geometric series to 8 terms, starting with 2 ​ and having a common ratio of 2 1 ​ , is 128 255 2 ​ ​ .
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Answered by Anonymous | 2025-07-04

Identify the first term a = 2 ​ and the common ratio r = 2 1 ​ .
Verify that ∣ r ∣ < 1 , confirming the series converges.
Apply the formula for the sum of the first n terms: S n ​ = a 1 − r 1 − r n ​ .
Substitute n = 8 , a = 2 ​ , and r = 2 1 ​ to find the sum: S 8 ​ = 128 255 2 ​ ​ .
The sum of the first 8 terms is 128 255 2 ​ ​ ​ .

Explanation

Identifying the Geometric Series We are given a geometric series and asked to find the sum of the first 8 terms. Let's first identify the key components of the series.

Finding the Common Ratio The first term of the series, denoted as a , is 2 ​ . The common ratio, denoted as r , is the ratio between consecutive terms. We can find it by dividing the second term by the first term: r = 2 ​ 2 ​ 1 ​ ​ = 2 ​ 1 ​ ⋅ 2 ​ 1 ​ = 2 1 ​

Verifying Convergence and Stating the Sum Formula Since the absolute value of the common ratio is less than 1 (i.e., ∣ r ∣ = ∣ 2 1 ​ ∣ < 1 ), the geometric series converges, and we can use the formula for the sum of the first n terms of a geometric series: S n ​ = a 1 − r 1 − r n ​

Substituting Values into the Formula We are asked to find the sum of the first 8 terms, so n = 8 . Substituting the values a = 2 ​ , r = 2 1 ​ , and n = 8 into the formula, we get: S 8 ​ = 2 ​ 1 − 2 1 ​ 1 − ( 2 1 ​ ) 8 ​ Now, let's simplify the expression.

Simplifying the Expression First, we calculate ( 2 1 ​ ) 8 = 2 8 1 ​ = 256 1 ​ . Then, we have: S 8 ​ = 2 ​ 1 − 2 1 ​ 1 − 256 1 ​ ​ = 2 ​ 2 1 ​ 256 256 − 1 ​ ​ = 2 ​ 2 1 ​ 256 255 ​ ​ = 2 ​ ⋅ 256 255 ​ ⋅ 2 = 2 ​ ⋅ 128 255 ​

Final Answer Therefore, the sum of the first 8 terms of the geometric series is 128 255 2 ​ ​ .


Examples
Geometric series are incredibly useful in many areas of science and engineering. For example, imagine a ball is dropped from a height of 1 meter, and each time it bounces, it reaches half of its previous height. The total distance the ball travels, both downwards and upwards, can be modeled as a geometric series. Understanding geometric series helps engineers design systems where energy loss occurs predictably, like in shock absorbers or electrical circuits.

Answered by GinnyAnswer | 2025-07-04