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In Mathematics / High School | 2025-07-03

In the sequence $6, 11, 16, \ldots$, which term is 236?

Asked by cassandrasj16

Answer (2)

Identify the sequence as arithmetic with first term a 1 ​ = 6 and common difference d = 5 .
Use the formula for the n -th term of an arithmetic sequence: a n ​ = a 1 ​ + ( n − 1 ) d .
Set a n ​ = 236 and solve for n : 236 = 6 + ( n − 1 ) 5 .
Find n = 47 , so the 47th term is 236. 47 ​

Explanation

Understanding the Problem We are given the arithmetic sequence 6 , 11 , 16 , … and we want to find which term is equal to 236.

Finding the Common Difference First, we need to find the common difference d of the sequence. We can find this by subtracting consecutive terms. d = 11 − 6 = 5 . So the common difference is 5.

General Formula The general formula for the n -th term of an arithmetic sequence is given by a n ​ = a 1 ​ + ( n − 1 ) d , where a 1 ​ is the first term and d is the common difference. In this case, a 1 ​ = 6 and d = 5 .

Setting up the Equation We want to find the term number n such that a n ​ = 236 . So we set up the equation: 236 = 6 + ( n − 1 ) 5

Solving for n Now we solve for n :
236 = 6 + 5 ( n − 1 ) 230 = 5 ( n − 1 ) 5 230 ​ = n − 1 46 = n − 1 n = 46 + 1 n = 47

Final Answer Therefore, the 47th term of the sequence is 236.


Examples
Arithmetic sequences are useful in many real-life situations, such as calculating simple interest, predicting patterns, and determining the number of seats in an auditorium where each row has a fixed number of additional seats. For example, if you deposit a fixed amount into a savings account each month, the total amount in your account over time forms an arithmetic sequence. Understanding arithmetic sequences helps in financial planning and forecasting.

Answered by GinnyAnswer | 2025-07-03

The 47th term of the arithmetic sequence 6 , 11 , 16 , … is 236. The common difference in the sequence is 5, and the formula used to find the term number is a n ​ = a 1 ​ + ( n − 1 ) d . Thus, solving for n gives us 47.
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Answered by Anonymous | 2025-07-04