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In Mathematics / College | 2025-07-03

Solve on the interval $\left[0^{\circ}, 360^{\circ}\right)$. Hint: Use an Identity!

$2 \sec ^2 x+\tan ^2 x=3$

Asked by brittpsj

Answer (2)

Use the identity sec 2 x = 1 + tan 2 x to rewrite the equation in terms of tan 2 x .
Solve for tan 2 x to get tan 2 x = 3 1 ​ .
Take the square root of both sides to get tan x = ± 3 ​ 1 ​ .
Find the angles x in the interval [ 0 ∘ , 36 0 ∘ ) such that tan x = 3 ​ 1 ​ and tan x = − 3 ​ 1 ​ , which are 3 0 ∘ , 15 0 ∘ , 21 0 ∘ , 33 0 ∘ . The final answer is { 3 0 ∘ , 15 0 ∘ , 21 0 ∘ , 33 0 ∘ } ​ .

Explanation

Understanding the Problem We are asked to solve the trigonometric equation 2 sec 2 x + tan 2 x = 3 on the interval [ 0 ∘ , 36 0 ∘ ) . We will use trigonometric identities to simplify the equation and find the solutions within the given interval.

Using Trigonometric Identity We know the trigonometric identity sec 2 x = 1 + tan 2 x . We can use this identity to rewrite the given equation in terms of tan 2 x .

Substitution Substitute sec 2 x = 1 + tan 2 x into the equation 2 sec 2 x + tan 2 x = 3 :
2 ( 1 + tan 2 x ) + tan 2 x = 3

Simplifying the Equation Simplify the equation: 2 + 2 tan 2 x + tan 2 x = 3 3 tan 2 x = 1

Solving for tan 2 x Solve for tan 2 x :
tan 2 x = 3 1 ​

Taking the Square Root Take the square root of both sides: tan x = ± 3 ​ 1 ​

Finding the Angles Find the angles x in the interval [ 0 ∘ , 36 0 ∘ ) such that tan x = 3 ​ 1 ​ and tan x = − 3 ​ 1 ​ .
For tan x = 3 ​ 1 ​ , the reference angle is 3 0 ∘ . Since tangent is positive in the first and third quadrants, the solutions are x = 3 0 ∘ and x = 18 0 ∘ + 3 0 ∘ = 21 0 ∘ .
For tan x = − 3 ​ 1 ​ , the reference angle is 3 0 ∘ . Since tangent is negative in the second and fourth quadrants, the solutions are x = 18 0 ∘ − 3 0 ∘ = 15 0 ∘ and x = 36 0 ∘ − 3 0 ∘ = 33 0 ∘ .

Final Answer Therefore, the solutions are x = 3 0 ∘ , 15 0 ∘ , 21 0 ∘ , 33 0 ∘ .


Examples
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Answered by GinnyAnswer | 2025-07-03

To solve the equation 2 sec 2 x + tan 2 x = 3 , we used the identity sec 2 x = 1 + tan 2 x to rewrite and simplify the equation to find tan 2 x = 3 1 ​ . This led to the solutions x = 3 0 ∘ , 15 0 ∘ , 21 0 ∘ , 33 0 ∘ within the interval [ 0 ∘ , 36 0 ∘ ) .
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Answered by Anonymous | 2025-07-04