Expand the original expression: ∑ n = 1 60 ( 2 n − 1 ) 2 = ∑ n = 1 60 ( 4 n 2 − 4 n + 1 ) .
Rewrite the sum: ∑ n = 1 60 ( 4 n 2 − 4 n + 1 ) = 4 ∑ n = 1 60 n 2 − 4 ∑ n = 1 60 n + ∑ n = 1 60 1 .
Simplify the constant term: ∑ n = 1 60 1 = 60 .
The equivalent expression is: 4 ∑ n = 1 60 n 2 − 4 ∑ n = 1 60 n + 60 .
Explanation
Understanding the Problem We are given the expression ∑ n = 1 60 ( 2 n − 1 ) 2 and we need to find equivalent expressions from the list.
Expanding the Expression First, let's expand the term inside the summation: ( 2 n − 1 ) 2 = 4 n 2 − 4 n + 1 . So, the original expression can be written as ∑ n = 1 60 ( 4 n 2 − 4 n + 1 ) .
Analyzing the Options Now, let's analyze the given options:
Option 1: ∑ n = 1 60 4 n 2 − 4 n − 1 . This can be written as ∑ n = 1 60 ( 4 n 2 − 4 n − 1 ) . Comparing this with ∑ n = 1 60 ( 4 n 2 − 4 n + 1 ) , we see that they are not equal.
Option 2: 4 ∑ n = 1 ∞ n 2 − 4 ∑ n = 1 ∞ n + ∑ n = 1 ∞ 1 . This involves summation to infinity, while our original expression is a finite sum up to 60. So, this option is not equivalent.
Option 3: 4 ∑ n = 1 ∞ n 2 − 4 ∑ n = 1 ∞ n − ∑ n = 1 ∞ 1 . Similar to option 2, this also involves summation to infinity, so it's not equivalent.
Option 4: 4 ∑ n = 1 60 n 2 − 4 ∑ n = 1 60 n + 60 . Let's rewrite our original expression: ∑ n = 1 60 ( 4 n 2 − 4 n + 1 ) = ∑ n = 1 60 4 n 2 − ∑ n = 1 60 4 n + ∑ n = 1 60 1 = 4 ∑ n = 1 60 n 2 − 4 ∑ n = 1 60 n + ∑ n = 1 60 1 . Since ∑ n = 1 60 1 = 60 , we have 4 ∑ n = 1 60 n 2 − 4 ∑ n = 1 60 n + 60 . This is exactly the same as option 4.
Final Answer Therefore, the equivalent expression is 4 ∑ n = 1 60 n 2 − 4 ∑ n = 1 60 n + 60 .
Examples
Understanding series and summations is crucial in many fields, such as physics and engineering. For example, when calculating the total energy of a system with multiple components, you might use a summation to add up the energy of each component. Similarly, in finance, you might use summations to calculate the total return on an investment over a period of time. The ability to manipulate and simplify these expressions can greatly aid in these calculations.
The equivalent expression for ∑ n = 1 60 ( 2 n − 1 ) 2 is 4 ∑ n = 1 60 n 2 − 4 ∑ n = 1 60 n + 60 , which matches option 4 in the list provided.
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