Substitute y = − 5 x into the first equation: 9 x + 3 ( − 5 x ) = − 30 .
Simplify and solve for x : 9 x − 15 x = − 30 ⇒ − 6 x = − 30 ⇒ x = 5 .
Substitute x = 5 into y = − 5 x to find y : y = − 5 ( 5 ) = − 25 .
The solution is ( 5 , − 25 ) , so the answer is ( 5 , − 25 ) .
Explanation
Understanding the Problem We are given a system of two equations with two variables x and y. The goal is to solve this system using the substitution method. The equations are:
9 x + 3 y = − 30 − 5 x = y
Substitution We will substitute the expression for y from the second equation into the first equation. The second equation is y = − 5 x . Substituting this into the first equation, we get:
9 x + 3 ( − 5 x ) = − 30
Simplifying the Equation Now, we simplify the equation:
9 x − 15 x = − 30
Combining Like Terms Combining like terms, we have:
− 6 x = − 30
Solving for x Now, we solve for x by dividing both sides by -6:
x = − 6 − 30 = 5
Solving for y Next, we substitute the value of x back into the second equation to find y :
y = − 5 ( 5 ) = − 25
The Solution Therefore, the solution to the system of equations is x = 5 and y = − 25 . We write the solution as an ordered pair ( x , y ) .
Final Answer The solution to the system of equations is ( 5 , − 25 ) .
Examples
Systems of equations are used in many real-world applications, such as determining the break-even point for a business, modeling supply and demand in economics, and solving for unknown variables in physics and engineering. For example, if you are running a business, you might use a system of equations to determine how many products you need to sell to cover your costs and start making a profit. Similarly, engineers use systems of equations to analyze the forces acting on a structure and ensure its stability.
To solve the system of equations 9 x + 3 y = − 30 and − 5 x = y , we substitute − 5 x into the first equation, simplify, and find x = 5 and y = − 25 . The final solution is ( 5 , − 25 ) .
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