An electric device delivers a current of [tex]$15.0 A$[/tex] for 30 seconds. How many electrons flow through it?

Compare the standard deviations of the seasons in each statement.
Determine if the statement is true based on the comparison.
The standard deviation of 2005 (3.5) is greater than the standard deviation of 2006 (2.8).
Therefore, the game scores of season 2005 have a greater spread than the game scores of season 2006. T r u e ​

Explanation

Analyze the problem and data We are given the mean and standard deviations of game scores for a football team across four seasons. The standard deviation tells us how spread out the data is. A larger standard deviation means a greater spread. We need to compare the standard deviations of the seasons mentioned in the given statements to determine which statement is true.

Compare standard deviations Let's analyze each statement:

The game scores of season 2006 have a greater spread than the game scores of season 2008. The standard deviation for 2006 is 2.8, and for 2008 is 4.0. Since 2.8 < 4.0, this statement is false.

The game scores of season 2007 have a greater spread than the game scores of season 2005. The standard deviation for 2007 is 1.0, and for 2005 is 3.5. Since 1.0 < 3.5, this statement is false.

The game scores of season 2006 have a greater spread than the game scores of season 2005. The standard deviation for 2006 is 2.8, and for 2005 is 3.5. Since 2.8 < 3.5, this statement is false.

The game scores of season 2005 have a greater spread than the game scores of season 2006. The standard deviation for 2005 is 3.5, and for 2006 is 2.8. Since 3.5 > 2.8, this statement is true.

Conclusion Therefore, the statement that must be true is: The game scores of season 2005 have a greater spread than the game scores of season 2006.


Examples
Understanding the spread of data, like football scores, is useful in many real-world scenarios. For example, in finance, standard deviation is used to measure the volatility of an investment. A higher standard deviation indicates a riskier investment because the returns are more spread out. Similarly, in weather forecasting, it can help understand the variability of temperature or rainfall.

Answered by GinnyAnswer | 2025-07-03

A current of 15.0 A flowing for 30 seconds results in a charge of 450.0 coulombs. This charge corresponds to approximately 2.81 x 10^21 electrons. Thus, around 2.81 trillion trillion electrons flow through the device during this time.
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Answered by Anonymous | 2025-07-04