How many moles are in 23.4 g of [tex]$CaCl_2$[/tex]?
Answer (2)
Calculate the molar mass of C a C l 2 : 40.08 + 2 × 35.45 = 110.98 g/mol .
Use the formula: moles = molar mass mass .
Substitute the given mass and calculated molar mass: moles = 110.98 23.4 .
Calculate the number of moles: 0.21 mol .
Explanation
Problem Analysis and Formula We are given 23.4 g of C a C l 2 and asked to find the number of moles. To do this, we will use the formula:
moles = molar mass mass
First, we need to calculate the molar mass of C a C l 2 .
Calculating Molar Mass The molar mass of C a C l 2 is the sum of the molar masses of one calcium atom (Ca) and two chlorine atoms (Cl).
The molar mass of Ca is approximately 40.08 g/mol. The molar mass of Cl is approximately 35.45 g/mol.
So, the molar mass of C a C l 2 is:
40.08 + 2 × 35.45 = 40.08 + 70.90 = 110.98 g/mol
Calculating Moles Now we can calculate the number of moles of C a C l 2 :
moles = 110.98 g/mol 23.4 g = 0.2108488015858713 mol
Rounding to two decimal places, we get 0.21 mol.
Final Answer Therefore, there are approximately 0.21 moles of C a C l 2 in 23.4 g.
Examples
In chemistry, determining the number of moles of a substance is crucial for calculating concentrations in solutions, understanding stoichiometry in chemical reactions, and performing quantitative analysis. For instance, if you're conducting an experiment that requires a specific molar concentration of C a C l 2 solution, you need to convert the desired number of moles into grams to accurately weigh out the solute. This conversion ensures the accuracy and reliability of your experimental results, which is essential in fields like pharmaceuticals, environmental science, and materials science.
There are approximately 0.21 moles of CaCl₂ in 23.4 g, calculated by determining the molar mass and using the formula for moles. The molar mass of CaCl₂ is 110.98 g/mol, which allows us to find the number of moles for the given mass. This calculation is essential in chemistry for understanding the quantities involved in chemical reactions.
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