What is the range of the function $y=\sqrt[3]{x+8}$?
A. $-\infty$
B. $-8$
C. $0 \leq y<\infty$
D. $2 \leq y<\infty$
Answer (2)
The function is y = 3 x + 8 .
The cube root function is defined for all real numbers.
The expression x + 8 can take any real value.
Therefore, the range of the function is − ∞ < y < ∞ , meaning all real numbers. $\boxed{-\infty
The function y = 3 x + 8 can take on all real number values because the cube root function is defined for all real inputs. Therefore, the range of this function is ( − ∞ , + ∞ ) . The closest option provided is A. − ∞ .
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