Rupinder gave \(\frac{7}{15}\) kilograms of berries to China from \(\frac{13}{15}\) kilograms of berries. Now how many kilograms of berries does Rupinder have left?
Find the product of the given fractions:
(a) \(\frac{1}{4} \times \frac{1}{3}\)
(b) \(\frac{1}{3} \times \frac{2}{11}\)
(c) \(\frac{1}{6} \times \frac{1}{2}\)
(d) \(\frac{7}{12} \times \frac{23}{18}\)
Solve:
(i) \(46 \times \frac{1}{2} =\) \(\frac{1}{2}\) of \(46\)
(ii) \(\frac{1}{3} \times \frac{1}{6} =\) \(\frac{1}{6}\) of \(\frac{1}{6} =\)
(iii) \(\frac{11}{5} \times \frac{1}{2} =\)
(iv) \(\frac{11}{4}\) of \(\frac{1}{2} =\) \(\frac{11}{5}\) of \(\frac{1}{2} =\)
Answer (1)
To solve the problems given, let's break each part down step by step.
1. Finding How Many Kilograms of Berries Rupinder Has Left
Rupinder originally had 15 13 kilograms of berries. He gave 15 7 kilograms to China. To find out how many kilograms of berries Rupinder has left, subtract the given amount from the original amount:
15 13 − 15 7 = 15 6 = 5 2
So, Rupinder has 5 2 kilograms of berries left.
2. Finding the Product of Fractions
(a) 4 1 × 3 1
Multiply the numerators and the denominators:
4 × 3 1 × 1 = 12 1
(b) 3 1 × 11 2
3 × 11 1 × 2 = 33 2
(c) 6 1 × 2 1
6 × 2 1 × 1 = 12 1
(d) 12 7 × 18 23
12 × 18 7 × 23 = 216 161
3. Solving the Given Equations
(i) 46 × 2 1 = 2 1 of 46
Calculate 2 1 × 46 :
2 46 = 23
(ii) 3 1 × 6 1 = 6 1 of 6 1
3 × 6 1 × 1 = 18 1
(iii) 5 11 × 2 1
5 × 2 11 × 1 = 10 11
(iv) 4 11 of 2 1 = 5 11 of 2 1
First, 4 11 × 2 1 :
4 × 2 11 × 1 = 8 11
Then, 5 11 × 2 1 :
5 × 2 11 × 1 = 10 11
By following these steps, you can find the solutions to the given problems.
