In this problem, we want to calculate the probability that a randomly chosen group of 5 participants from a total of 10 participants (6 boys and 4 girls) contains at least two girls.
To solve this problem, we'll use combinations to find the number of ways to choose the group of participants and then apply probability rules.
Step-by-step solution:
Calculate the total number of ways to select 5 participants out of 10.
The total number of combinations is given by:
( 5 10 ) = 5 × 4 × 3 × 2 × 1 10 × 9 × 8 × 7 × 6 = 252
Calculate the number of ways to select groups with less than 2 girls (0 or 1 girl).
0 Girls (All Boys):
( 5 6 ) = 6
1 Girl and 4 Boys:
Number of ways to choose 1 girl out of 4: ( 1 4 ) = 4
Number of ways to choose 4 boys out of 6: ( 4 6 ) = 15
Total combinations for 1 girl: 4 × 15 = 60
Calculate the number of ways to select at least 2 girls.
At least 2 girls is the total number of combinations minus the combinations with less than 2 girls:
Total combinations = 252
Combinations with less than 2 girls = 6 (0 girls) + 60 (1 girl) = 66
Combinations with at least 2 girls = 252 - 66 = 186
Calculate the probability.
The probability that the group has at least two girls is:
252 186 ≈ 0.738
Thus, Gopal found that the probability that a randomly chosen group of 5 participants has at least two girls is approximately 0.738 (rounded to three decimal places).