Let's address each part of the question step by step.
a. Show that the increase in the contribution per member was: n ( n − 5 ) 18000 if n is the initial number of members.
Initially, the total amount required was 3600, and n members agreed to contribute equally. Therefore, each member's initial contribution is given by: C i = n 3600
When 5 members leave, the number of contributors becomes n − 5 . The new contribution per member is then: C n e w = n − 5 3600
The increase in contribution per member then follows from: C in cre a se = C n e w − C i = n − 5 3600 − n 3600
Combining these fractions over a common denominator gives: C in cre a se = n ( n − 5 ) 3600 n − 3600 ( n − 5 ) = n ( n − 5 ) 3600 × 5 = n ( n − 5 ) 18000
This proves the increase is indeed n ( n − 5 ) 18000 .
b. If the increase in the contribution per member was 24 , what was the original contribution before the other members left?
We know: n ( n − 5 ) 18000 = 24
Solving for n :
18000 = 24 n ( n − 5 ) n ( n − 5 ) = 750
We need to find integer solutions for n . Since n ( n − 5 ) = 750 , consider the quadratic equation: n 2 − 5 n − 750 = 0
Using the quadratic formula for roots n = 2 a − b ± b 2 − 4 a c , where a = 1 , b = − 5 , c = − 750 :
n = 2 5 ± 25 + 3000 = 2 5 ± 55
Calculating the roots:
n = 2 60 = 30
n = 2 − 50 = − 25 (not feasible as n must be positive)
Thus, n = 30 members initially.
The original contribution per member was: C i = 30 3600 = 120
c. Calculate the percentage increase in the contribution after the others left.
The increased contribution per member after 5 members left is: C n e w = 30 − 5 3600 = 25 3600 = 144
The increase is 144 − 120 = 24 . So, the percentage increase is: Percentage Increase = ( 120 24 ) × 100% = 20%
Thus, the contribution per member increased by 20% after 5 members left.